class method

SyntaxSuggest.valid_without?

valid_without?(without_lines:, code_lines:)

lib/syntax_suggest/api.rb View on GitHub ↗

# File tmp/rubies/ruby-4.0.0/lib/syntax_suggest/api.rb, line 146
def self.valid_without?(without_lines:, code_lines:)
  lines = code_lines - Array(without_lines).flatten

  lines.empty? || valid?(lines)
end

SyntaxSuggest.valid_without? [Private]

This will tell you if the code_lines would be valid if you removed the without_lines. In short it’s a way to detect if we’ve found the lines with syntax errors in our document yet.

code_lines = [
  CodeLine.new(line: "def foo\n",   index: 0)
  CodeLine.new(line: "  def bar\n", index: 1)
  CodeLine.new(line: "end\n",       index: 2)
]

SyntaxSuggest.valid_without?(
  without_lines: code_lines[1],
  code_lines: code_lines
)                                    # => true

SyntaxSuggest.valid?(code_lines) # => false

See also .valid? #detailed_message .use_prism_parser? also in 3.4 · 3.3 · 3.2

‹ prev.valid? next ›#detailed_message