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instance method

Hash#compare_by_identity

hash.compare_by_identity → self

VALUE
rb_hash_compare_by_id(VALUE hash)
{
    VALUE tmp;
    st_table *identtable;

    if (rb_hash_compare_by_id_p(hash)) return hash;

    rb_hash_modify_check(hash);
    ar_force_convert_table(hash, __FILE__, __LINE__);
    HASH_ASSERT(RHASH_ST_TABLE_P(hash));

    tmp = hash_alloc(0);
    identtable = rb_init_identtable_with_size(RHASH_SIZE(hash));
    RHASH_ST_TABLE_SET(tmp, identtable);
    rb_hash_foreach(hash, rb_hash_rehash_i, (VALUE)tmp);
    st_free_table(RHASH_ST_TABLE(hash));
    RHASH_ST_TABLE_SET(hash, identtable);
    RHASH_ST_CLEAR(tmp);

    return hash;
}

Sets self to consider only identity in comparing keys; two keys are considered the same only if they are the same object; returns self.

By default, these two object are considered to be the same key, so s1 will overwrite s0:

Example

s0 = 'x'
s1 = 'x'
h = {}
h.compare_by_identity? # => false
h[s0] = 0
h[s1] = 1
h # => {"x"=>1}

After calling #compare_by_identity, the keys are considered to be different, and therefore do not overwrite each other:

Example

h = {}
h.compare_by_identity # => {}
h.compare_by_identity? # => true
h[s0] = 0
h[s1] = 1
h # => {"x"=>0, "x"=>1}

See also #compare_by_identity? #compact! #compact #deconstruct_keys also in 4.1 · 4.0 · 3.4 · 3.3 · 3.1 · 3.0

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