SyntaxSuggest.valid?

valid?(source)

lib/syntax_suggest/api.rb View on GitHub ↗

# File tmp/rubies/ruby-3.3.0/lib/syntax_suggest/api.rb, line 211
def self.valid?(source)
  !invalid?(source)
end

SyntaxSuggest.valid? [Private]

Returns truthy if a given input source is valid syntax

Example

SyntaxSuggest.valid?(<<~EOM) # => true
  def foo
  end
EOM

SyntaxSuggest.valid?(<<~EOM) # => false
  def foo
    def bar # Syntax error here
  end
EOM

You can also pass in an array of lines and they’ll be joined before evaluating

Example

SyntaxSuggest.valid?(
  [
    "def foo\n",
    "end\n"
  ]
) # => true

SyntaxSuggest.valid?(
  [
    "def foo\n",
    "  def bar\n", # Syntax error here
    "end\n"
  ]
) # => false

As an FYI the CodeLine class instances respond to to_s so passing a CodeLine in as an object or as an array will convert it to it’s code representation.

See also .use_prism_parser? .valid_without? .record_dir #detailed_message also in 4.0 · 3.4 · 3.2

‹ prev.use_prism_parser? next ›.valid_without?